A simple method for writing Lewis Structures is given in a previous article entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Let us consider the case of the sulfite ion. The chemical formula is SO3-2.
What is the SO3-2 Lewis structure?
Step 1: Connect the atoms with single bonds. The central atom is the sulfur atom.
Fig. 1 : Connect the atoms of the sulfite ion (SO3-2) with single bonds. |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this case is 4 since SO3-2 consists of four atoms.
Where V = (6 + 6 + 6 + 6 ) – (-2) = 26 , V is the number of valence electrons of the ion.
Therefore, P = 6n + 2 – V = 6 * 4 + 2 – 26 = 0 So, there are no π electrons in SO3-2
Therefore, the structure in Step 1 is a plausible Lewis structure of SO3-2.
Electrons are placed around each atom so that the octet rule is obeyed. Since S is a third row element can accommodate more than 8 valence electrons.
Step 3 & 4: The Lewisresonance structuresof SO3-2 areas follows:
Fig. 2 : Lewis dot structures of SO3-2 |
Resonance Structures #1-#3 are more stable due to less charge separation - even though the S atom has more than 8 electrons - comparing to Structure #4. Structure #4 is less stable because of larger charge separation.
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