A simple procedure for writing Lewis Structures was given in a previous article entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Let us consider the case of chromic acid. The chemical formula is H2CrO4.
Step 1: Connect the atoms with single bonds.
Fig. 1: The H2CrO4 atoms connected with single bonds |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this case is 5, excluding the H atoms. Where V = (1 + 6 + 6 + 6+ 6 + 6 + 1) = 32 , V is the number of valence electrons of the molecule.
Therefore, P = 6n + 2 – V = 6 * 5 + 2 – 32 = 0 So, there is no multiple bond in the molecule.
Step 3 & 4: The resonance structures of H2CrO4 are as follows:
Fig. 2: Lewis electron dot structure of H2CrO4 |
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