Tampilkan postingan dengan label Theoretical Chemistry - Lewis Electron Dot Structures. Tampilkan semua postingan
Tampilkan postingan dengan label Theoretical Chemistry - Lewis Electron Dot Structures. Tampilkan semua postingan

Kamis, 24 Oktober 2013

Lewis dot structure of carbonic acid H2CO3

A simple procedure for writing electron Lewis dot structures was given in a previous post entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).


Let us examine the case of carbonic acid H2CO3. How can we draw the carbonic acid Lewis dot structure?

Step 1: Connect the atoms with single bonds. 


Fig. 1 : Connect the atoms of carbonic acid with single bonds
Fig. 1 : Connect the atoms of carbonic acid with single bonds

 Step 2:  Calculate the # of electrons in π bonds (multiple bonds) using  formula (1)


Where n in this case is 4 since H2CO3 consists of six atoms but two of them are H atoms.
Where V = (1 + 6 + 4 + 6 + 6 + 1) = 24 
Therefore, P = 6n + 2 – V = 6 * 4 + 2 – 24 = 2      So  there are 2 π electrons in H2CO3and therefore 1 double bond must be added to the structure of Step 1.

Step 3 & 4: The Lewis structure of H2COis derived below:

Fig. 2: Lewis structure of carbonic acid H2CO3
Fig. 2: Lewis structure of carbonic acid H2CO3

Rabu, 23 Oktober 2013

Electron Lewis Dot Structure of chlorosulphonic acid HSO3Cl

A simple procedure for writing electron Lewis dot structures was given in a previous post entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).


Let us examine the case of chlorosulphonic acid HSO3Cl . How can we construct the chlorosulphonic acid Lewis dot structure?

Step 1: Connect the atoms with single bonds. 

Fig. 1 : Connect the atoms of chlorine perchlorate with single bonds.
Fig. 1 : Connect the atoms of chlorosulphonic acid with single bonds.

 Step 2:  Calculate the # of electrons in π bonds (multiple bonds) using  formula (1)


Where n in this case is 5 since  HSO3Cl  consists of six atoms but one of them is a H atom.
Where V = (1 + 6 + 6 * 3 + 7) = 26 
Therefore, P = 6n + 2 – V = 6 * 5 + 2 – 32 = 0     So  there are no  π electrons in HSO3Cl  

Step 3 & 4: The Lewis structures of  HSO3Cl are derived below:
Fig. 2 : Plausible Lewis structure of the chlorosulphonic acid.
Fig. 2 : Plausible Lewis structure of the chlorosulphonic acid.