A simple procedure for writing electron Lewis dot structures was given in a previous post entitled “Lewis Structures and the Octet Rule”.
Several worked examples relevant to this procedure were given in previous posts please see the Sitemap - Table of Contents (Lewis Electron Dot Structures).
Let us examine the case of carbonic acid H2CO3. How can we draw the carbonic acid Lewis dot structure?
Fig. 1 : Connect the atoms of carbonic acid with single bonds |
Step 2: Calculate the # of electrons in π bonds (multiple bonds) using formula (1):
Where n in this case is 4 since H2CO3 consists of six atoms but two of them are H atoms.
Where V = (1 + 6 + 4 + 6 + 6 + 1) = 24
Therefore, P = 6n + 2 – V = 6 * 4 + 2 – 24 = 2 So there are 2 π electrons in H2CO3and therefore 1 double bond must be added to the structure of Step 1.
Step 3 & 4: The Lewis structure of H2CO3 is derived below:
Fig. 2: Lewis structure of carbonic acid H2CO3 |
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